A car is moving with a velocity of 72km when breaks applied it come to rest after 4 secands find the distance?
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72km/hr=20m/s
v=u+at
0=20+4a
a=-5m/s
s=ut+1÷2×a×t^2
s=20×4+1÷2×-5×16
s=80-40
s=40 m
v=u+at
0=20+4a
a=-5m/s
s=ut+1÷2×a×t^2
s=20×4+1÷2×-5×16
s=80-40
s=40 m
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