Question

a car is moving with the speed of 36 km per hour comes to rest in 5 second by applying brakes calculate the acceleration and distance covered by the car before coming to rest

Answer 1

Initial velocity of car=36km/h or 10m/s
Final velocity of car=0m/s
Time taken by the car to come to rest=5s
Acceleration=?
By using the first equation of motion we can find out the acceleration of the car, so:
v=u+at
0=10+5a
-10=5a
-2=a
-2m/s is the retardation (acceleration done in opposite direction) of the car.
Now, we need to find the distance travelled by the car before coming to rest. In order to find out the distance we have to use second equation of motion:
s=ut+1/2at^2
s=10×5+1/2×-2×25
s=50+(-25)
s=25m
So, the distance travelled by the car before coming to rest is 25m.
Hope you like this answer and if it helps you please mark it brainliest.