Question

determine AP whose third term 16 and the 7th term exceeds the 5th term by 12

Answer 1

4,10,16,22... it will be the required arithmetic progression

Answer 2

Answer

a3 = 16

=> a + 2d = 16

=> a = 16 - 2d

a7 = a5 + 12

=> a + 6d = a + 4d + 12

=> 2d= 12

=> d = 6

a = 16 - 2d

=> a = 16 - 12

=> a = 4

AP = 4, 10, 16...