Question

A car is moving with the speed of 72 km/hr. If it stops in 10 seconds. Find the distance travelled by it​

Answer 1

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Initial Velocity : 72 km/h = 20 m/s

Final Velocity : 0 km/h = 0 m/s

Time taken : 10 s

Final velocity = Initial velocity + acceleration × time

0 m/s = 20 m/s + a × 10 s

20 m/s = a × 10 s

a = (20 m/s)/(10 s)

a = 2 m/s²

Distance = ut + ½at²

$s = 20 \: m {s}^{ - 1} \times 10 \: s + \frac{1}{2} \times 2 \: m {s}^{ - 2} \times {(10 \: s)}^{2}$

$s = 200 \: m + \frac{1}{2} \times 2 \: m {s}^{ - 2} \times 100 \: {s}^{2}$

$s = 200 \: m + 100 \: m$

$s = 300 \: m$