Question

A car is moving with the velocity of 54 km/h. Uniform

deceleration 2.5 m/s2

is produced by applying brakes. Find the distance travelled by the

car after applying brakes.​

Answer 1

$given: \\ u = 54km {h}^{ - 1} \\ = 54 \times \frac{5}{18} m {s}^{ - 1} \\ = 15m {s}^{ - 1} \\ a = - 2.5m {s}^{2} \\ v = 0 \\ \\ formula = {v}^{2} - {u}^{2} = 2as\\ \\ {(0)}^{2} - {(15)}^{2} = 2 \times - 2.5 \times s \\ - 225 = - 5 \times s \\ s = \frac{ - 225}{ - 5} \\ s = 45m \: ans:$

$\huge \mathfrak \color{gold}{thnq}$