A car is moving with uniform acceleration of 5 M per second square find its velocity after 20 seconds if it started from rest also find distance covered
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from 1 equation of motion
v=u+at
v=0+5x20
v=100m/s
displacement --from 3rd equation of motion
s=ut +1/2 at^2
s=0+0.5x5x20x20
s=1000m
v=u+at
v=0+5x20
v=100m/s
displacement --from 3rd equation of motion
s=ut +1/2 at^2
s=0+0.5x5x20x20
s=1000m
Answered by
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acceleration=5m/s2
uniform velocity=0m/s
timetaken=20s
finalvelocity=u + at
=0 + 5*20
=100m/s
distance=u + v / 2 *t
=0+100/2* 20
=50*20
=1000m
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