Question

a car is moving with velocity 108 km/h if the driver of the car wants to change its velocity from 108 km/h to 90 km/h in 2 minutes.Mass of the car is 300 kg. What force is applied by the brakes on the tyres?

Answer 1

108km/h = 108×5/18 m/s = 30m/s
90km/h = 90×5/18 = 25m/s

a = (u - v)/t
a = (30 - 25)/(2 × 60)
a = 1/24 m/s²

F = ma
F = 300 × 1/24
F = 12.5 N

Force applied by the brakes on the tyres is 12.5N

Answer 2

TWISTY QUES

SEE,

108km/h=30m/s

90km/h=25m/s

a=v-u/t

a=25-30/60×2

a=-5/120

a=-1/24

so,as we know f=ma

f=300×-1÷24

f=-300÷24

f=-12.5

AND DONE