Physics, asked by bridzerazz71, 9 months ago

A car is moving with velocity 15 m/s and slows down to 5 m/s with retardation 2 m/s.Calculate the time taken to do so and distance covered with the time.

Answers

Answered by saikethansaikethan
2

Answer:

t=5sec and distance=50m

Explanation:

u=15m/s,v=5m/s

t=?,a=-2

v=u+at

t=5sec

by substituting in formula v^2-u^2=2as

s=50m

hope, it helps you.

Similar questions