A car is moving with velocity 15 m/s and slows down to 5 m/s with retardation 2 m/s.Calculate the time taken to do so and distance covered with the time.
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Answer:
t=5sec and distance=50m
Explanation:
u=15m/s,v=5m/s
t=?,a=-2
v=u+at
t=5sec
by substituting in formula v^2-u^2=2as
s=50m
hope, it helps you.
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