Question

Find the area of a triangle, two sides of which are 33 cm and 38 cm and the perimeter is 110 cm.using herons formula
s =semiperimeter=p/2

$\sqrt{s( s-a )( s-b )( s-c )}$
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Answer 1

Answer:

110=33+38+x

110=71+x

110-71=x

39=x

s=33+38+39/2

s=55

area=√[s(s-a)(s-b)(s-c)]

√55(55-33)(55-38)(55-39)

√55×22×17×16

44√170