a car is moving with velocity v it comes to rest when the brakes are applied. what are the changed equation of motions?
Answers
Answer
When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity (v0) and the braking capacity, or deceleration, -a that is caused by the braking. Derive an expression for stopping distance of a vehicle in terms of v0
Explanation
Initial Velocity( u) = 12 m/s
Final Velocity ( v) = 0 m/s
It comes to rest in 6 sec
To find : a= ?
distance covered in this time period = ?
Solution
v = u + at
0 = 12 + a× 6
-12/6= a
a= -2 m/sec²
distance
( I ) s= ut +1/2 at²
(II) 2as = v²-u²
by II formula
2×(-2) × s= (0)²-(12)²
-4s= -144
s= 36 m
by l formula
s = (0)×6+1/2×(2)(6)²
s= 0+1(36)
s=36 m
Answer:
A car of mass 450 kg is moving with velocity 72 On applying brakes the car hr comes to rest before covering a distance of 8