A car is purchased for ₹ 640000. its value depreciates at the rate of 10% per annum. find value after (a) 2 years (b) 3 years
Answers
Answered by
1
Answer:
Price Of The Car= Rs 640000
Per annum, it's total value will be depreciated by 10%,that's 10% of 640000=64000,so 64000 is depreciated every year
a) at 2 years,it will be 2x,where x=64000
2x=2×64000=128000
Total value- Depreciation= 640000-128000=512000
b) at 3 years,it will be 3x,where x=64000
3x=3×64000=192000
Total Value-Depreciation=
640000-192000=448000
hope it helps
Answered by
2
Answer:
Answer of (a) = 518400
A = P (1 - R/100) ^n
= 640000 ( 1 - 10/100)^ 2
= 640000 ( 9/10)^2
= Rs 518400
Answer of (b) = Rs 466560
A = P (1 - R/100)^n
= 640000 (1 - 10/100)^3
= 640000 ( 9/10)^3
= Rs 466560
Please mark me as a brainliest
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