a car is running at 25km/h can be brought to rest by applying brakes in a distance of 0.5 m. If the same car is running at 75km/h how far will it go before coming to rest, if the braking force remains the same?
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64
Here's your answer friend.
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v^2 = u^2 - 2as
0 = 6.94^2 - 2× a × 0.5
a = 48.16 m/s^2
Now
if u = 75 km/hr = 20.83 m/s
v = 0
abd force applied is same this means the acceleration is the same as calculated above
a= 48.16 m/s^2
Now
again from the third equation of motion
v^2 = u^2 - 2as
0^2 = 20.83^2 - 2×48.16 × s
s = 4.5 m
0 = 6.94^2 - 2× a × 0.5
a = 48.16 m/s^2
Now
if u = 75 km/hr = 20.83 m/s
v = 0
abd force applied is same this means the acceleration is the same as calculated above
a= 48.16 m/s^2
Now
again from the third equation of motion
v^2 = u^2 - 2as
0^2 = 20.83^2 - 2×48.16 × s
s = 4.5 m
singarapusreehanth6:
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