Question

. A car is running at a speed of 54 km h–1

. In the next

second, its speed is 63 km h–1

. Calculate the distance

covered by the car in m.

Answer 1

convert to meters
intial velocity = 15ms^2
final velocity = 17.5 ms^2
acceleration = v-u/t
17.5 - 15 / 1
2.5ms^2
distance = ut + 1/2at^2
15 × 1 + 1/2 × 2.5 × 1 ×1
15 + 1.25
16.25 m
hope it helps u..✌✌

Answer 2

54km/hr = 15m/s
63=17.5
v=u+at
17.5=15+a
a=2.5
s=ut+1/at^2
s=16.5m
this is tentative answer
it should be done by calculus which is out of your syllabus