Question

a car is speeding along at 25mper second. the breaks the 500kg car to a speed of 3 m per secound. over a distance of 5 m. determine the force applied by breaks and the work done by the car on the breaks​

Answer 1

Answer:

-154000J

Explanation:

initial velocity(u)= 25m/s

final velocity(v)= 3m/s

mass(m)= 500kg

displacement (s)= 5m

acceleration(a)= $\frac{V^{2}-U^{2} }{2S}$

       =(3)2-(25)2/2x5

          =9-625/10

          =(-61.6m/s2)

force(f)= ma

          =500x(-61.6)

           =(-30800)N

work done = fs

         =(-30800)x5

           =    -154000J