Sum the following series :
(i) 2 + 4 + 6 + ...... to n terms
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a = 2
d = 2
Sn = 2a + ( n - 1) d
Sn = 2 × 2 + ( n - 1) × 2
Sn = 4 + 2n - 2
Sn = 2 + 2n
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