Question

A car is traveling at 21.0 m/s. It slows to a stop at a constant rate over 5.00 s. How far does the car travel during those 5.00 seconds before it stops?

Answer 1

Answer:

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Answer 2

Answer:

Correct option is

B

8.10 m s

−2

using second eq of motion s=ut+1/2at

2

as u=0, a=

t

2

2s

=

5.21

2

2∗110

=8.10m/s

2

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