Question

A car is traveling at a speed of 90 km/h. Brakes are applied so as to produce a uniform acceleration of – 0.5 m/s . Find how far the car will go before it is brought to rest?

Answer 1

GiveN :

• Initial velocity (u) = 90 km/h = 25 m/s
• Final velocity (v) = 0 m/s
• Acceleration (a) = - 0.5 m/s²

To FinD :

• Distance travelled by car after applying breaks.

SolutioN :

Use 3rd equation of Kinematics :

⇒v² - u² = 2as

⇒0² - 25² = 2 * -0.5 * s

⇒0 - 625 = -1 * s

⇒s = 625 m

$\small \therefore \: \sf{Distance \: travelled \: by \: car \: after \: applying \: breaks \: is \: 625 \: m}$

Answer 2

Answer:

Use 3rd equation of Kinematics :

⇒v² - u² = 2as

⇒0² - 25² = 2 * -0.5 * s

⇒0 - 625 = -1 * s

⇒s = 625 m

{\small \therefore \: \sf{Distance \: travelled \: by \: car \: after \: applying \: breaks \: is \: 625 \: m}}