A car is traveling on a highway at a speed 25m/s. A
passenger in a car throws a ball at an angle
37° with horizontal in a plane perpendicular the
motion of the car. The ball is projected with a speed
of 10m/s relative to car. What may be the initial
velocity of ball in unit vector rotation.
X
Z
Answers
Answer:
I hope. Z is your answer
Initial Velocity of Ball = 33 i + 6j
Explanation:
Step by Step Solution :
Given :
Initial velocity of car (assumed in i direction) = 25i + 0j + 0k
Relative velocity of ball (with respect to car) = 10 m/s in direction vertical to plane of moving car
Angle of projection of ball from horizontal (i.e. i unit vector / axis) = 37°
Step-1 : Relative velocity of ball with respect to car is written in 3 dimensional cartesian coordinates as follows : 10 cos37° i + 10 sin37° j (since it is projected in a plane perpendicular to the plane of motion of car)
Step-2 : Absolute initial velocity of ball = Initial velocity of car + Relative velocity of ball with respect to car (as per rule of relative velocity)
Step-3 : Absolute initial velocity of ball = 25 i + (10cos37° i + 10sin37° j) = (25 + 10cos37°) i + 10sin37° j = {25 + 10(0.8)} i + 10(0.6) j = 33 i + 6 j