A car is travelling along a flyover bridge which is a part of vertical circle of radius 10m. At the highest point of it the normal reaction on the car is half of it’s weight, the speed of car is
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Answer:
Normal reaction is half its weight
⇒N=
2
mg
Net force which provides centripetal force is
mg−
2
mg
=
R
mv
2
→v=
2
Rg
=
2
9.8×10
=7m/s
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Answer:
travelling along along of lower bridge which is the part of vertical circle of radius 10 metre the highest point of normal reaction on the car is half of the Earth weight the speed of car is time is equal to 10 minute radius is equal to 10 metre is equal to 10 + 10 is equal to 20 and 20 + 20 is equal to 40 so the answer will be coming now 7 metre per second square
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