Question

A car is travelling along the road at 8m/s. It accelerates at 1 ms-2 for a distance of 18 m. How fast is it then travelling?

Answer 1

Using Newton's law of motion, $v^{2} - u^{2} =2as$

where v is the final velocity, u is the initial velocity a is the acceleration and s is the distance traveled.

=> $v^{2}$ - 8*8 = 2*1*18
=> $v^{2}$ = 36+64
=> v = 10 m/s

Answer 2

Answer:

Answer ♡

Using Newton's law of motion,

$v^{2} - u^{2} =2as$

• where v is the final velocity, u is the initial velocity a is the acceleration and s is the distance traveled.

=> $v^{2}$ - 8*8 = 2*1*18

=> $v^{2}$ = 36+64

=> v = 10 m/s