Physics, asked by manjudewangan12, 9 months ago

A car is travelling along the rod at 20 m/s along a road. A child runs out into road 50 m ahead and a car driver steps on a brake pedal. What must the car deceleration be if the car is to stop just before it reaches the child ?

Answers

Answered by BrainlyConqueror0901
19

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Deceleration\:of\:bus=4\:m/s^{2}}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given :}} \\  \tt:  \implies Initial \: speed(u) = 20 \: m/s \\  \\  \tt:  \implies Final\:speed(v)= 0 \: m/s \\  \\  \tt: \implies Distance(s) = 50 \: m \\  \\ \red{\underline \bold{To \: Find :}} \\  \tt:  \implies Deceleration(a) = ?

• According to given question :

 \bold{As \: we \: know \: that} \\  \tt:  \implies v^{2} =u^{2}  +2as   \\  \\  \text{Putting \: given \: value} \\  \tt:  \implies 0^{2} = 20^{2}+2 \times a\times 50   \\  \\  \tt:  \implies 0 =400 + 100\times a \\\\ \tt{:\implies -400=100\times a}\\  \\ \tt:  \implies a=\frac{-400}{100} \\  \\  \green{\tt:  \implies a =-4 \: m/s^{2}} \\  \\    \tt\green{\therefore  Deceleration \: of \:bus  \: is \:  \: 4 \: m/s^{2}} \\  \\   \blue{\bold{Some \: formula \: realted \: to \: this \: topic}} \\   \orange{\tt \circ \: v = u + at }\\  \\  \orange{\tt \circ \:  s=  ut +\frac{1}{2}at^{2}}

Answered by Saby123
8

</p><p>\huge{\pink{\tt{Hello!!! }}} \\ \\</p><p></p><p></p><p>\tt{\green{Given \: - }}

</p><p>\tt{\purple{=&gt;U\: = \:20 \:m/s }} \\ \\ </p><p>\tt{\blue{=&gt;V \:= \:0 \:m/s }} \\ \\ </p><p>\tt{\red{=&gt;S\: =\: 50 \:m }}

</p><p>\huge{\fbox {\fbox{\rightarrow {\mathfrak {\orange{{V}^2 = {U}^2 + 2.a.s }}}}}}

</p><p>\tt{\purple{Where = &gt;\begin{cases}</p><p></p><p>U &amp; \text{20\: m/s} \\</p><p>\\</p><p>V &amp; \text{0 \: m/s}</p><p>\\ \\</p><p>S &amp; \text{50 \: m }</p><p>\end{cases}}}

Solving We Get : -

</p><p>\tt{\orange{\boxed {\boxed {A \: = \: -4 \: m/s. }}}}

________________________

OTHER RELATED FORMULAS :

</p><p>\huge{\fbox {\fbox{\rightarrow {\mathfrak {\orange{V = U + 2.a.t }}}}}}

</p><p>\huge{\fbox {\fbox{\rightarrow {\mathfrak {\orange{{V}^2 = {U}^2 + 2.a.s }}}}}}

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