Question

a car is travelling at 24 m/s along a straight road. the driver applies the brakes and the car undergoes a uniform deceleration of 6 m/s2

Answer 1

Answer:

4 sec

Explanation:

The time when car stops will be = (24-0 m/s )/6 m/s²

= 4 sec

Answer 2

Explanation:

velocity of car,u=24m/s

deacceleration =6 m/s2

Time taken for the car to come to rest =t

distance travelled by car before coming to rest=s

now v=u+at

0=24-6t

6t=24

t=4 sec

now distance

s=ut+1/2at×t

=24×4+1/2×-6×16

=96-48

=48m