a car is travelling at 72kmph, brakes are applied so as to produce a uniform acceleration of -0.5m/s square. then how much distance will the car take to come to rest
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Answer:
The answer is in the picture
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Explanation:
(Initialvelocity=72km/hr=72*5/18=20m/s)
By using IIIrd eq.of motion
Finalvelocity^2=2*acceleration*dis.+initial velocity^2
=0^2=2*(-0.5)s+(20^2)
0=-1s+400
1s=400
So, 400m.s ans....
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