Question

A car is travelling at a speed of 36 km/hr. The driver applies brakes and retards the car uniformly. The car is stopped in 5s. Find the distance travelled before it stopped after applying brakes

Answer 1

let the initial speed be u=36km/h=10m/s    (multiply by 5/18 to convert)

the car stooped in t=5 secs

v=u+at     as car stopes finally final velocity v becomes zero

0=10+a*5

a=-2              (negative as car is retarding)

now use newtons second eq of motion

s=ut+1/2*a*t²

s=10*5+-1*25

s=50-25m

s=25m

Answer 2

Answer:

Step-by-step explanation:

et the initial speed be u=36km/h=10m/s    (multiply by 5/18 to convert)

the car stooped in t=5 secs

v=u+at     as car stopes finally final velocity v becomes zero

0=10+a*5

a=-2              (negative as car is retarding)

now use newtons second eq of motion

s=ut+1/2*a*t²

s=10*5+-1*25

s=50-25m

s=25m