Question

a car is travelling at a speed of 36 km/hr. the driver applies brakes and retards the car uniformly. the car is stopped in 5s. find the distance travelled before it stopped after applying breakes

Answer 1

$s = ut + 0.5a {t}^{2}$
converting speed in m/s
=36×5/18
=10m/s

v = u + at
0=10 + a × 5
-10=5a
a = -2m/s^2

s=10×5 + 0.5(-2)×5×5
s=50-25
s = 25m

Answer 2

Answer:

Explanation:

S=ut + 0.5at²

converting speed in m/s

=36×5/18

=10m/s

v = u + at

0=10 + a × 5

-10=5a

a = -2m/s^2

s=10×5 + 0.5(-2)×5×5

s=50-25

s = 25m