Question

A car is travelling at a velocity of 36km/h.if it's velocity increases to 72km/h in 10s find the acceleration of the car

Answer 1

initial velocity, u=36 km/h

final velocity, v=72 km/h

time, t=10 s=10/3600=0.0027 hr

acceleration, a=v-u/t=72-36/0.0027=13333.3333km/h^2

Hope it helps

Thanks

Answer 2

Question:-

A car is travelling at a velocity of 36km/h.

if it's velocity increases to 72km/h in 10s. find the acceleration of the car ?

Given:-

a) A car is travelling at a velocity

of 36km/h.

b) A velocity of car increases to

72km/h in 10s.

Formula:-

${ \dashrightarrow{ \bf{ \huge{ \red{a} = { \frac{v - u}{t} }}}}}$

where,

--» a = acceleration

--» v = final velocity

--» u = initial velocity

--» t = time taken by object ( body )

Solution:-

To find acceleration of car

We know

--» 1 km = 1000 meter

--» 1 hour = {60×60} sec = 3600 sec

{ Acccording to question }

--» u = 36 km/h

${ \bf{ \dashrightarrow{u = [\frac{36 \times 1000}{60 \times 60} ]m/s}}}$

${ \bf{ \dashrightarrow{u = [{\frac{36000}{3600} }]}m/s}}$

${ \bf{ \dashrightarrow{u = 10 \: m/s}}}$

--» v = 72 km/h

${ \bf{ \dashrightarrow{v = [\frac{72 \times 1000}{60 \times 60} ]m/s}}}$

${ \bf{ \dashrightarrow{v = [\frac{72000}{3600} ]m/s}}}$

${ \bf{ \dashrightarrow{v = 20 \: m/s}}}$

also we know that

--» t = 10 sec

now, by formula

${ \dashrightarrow{ \bf{ \red{a} = { \frac{v - u}{t} }}}}$

${ \dashrightarrow{ \bf{ \red{a} = { \frac{20 - 10}{10} }}}}$

${ \dashrightarrow{ \bf{ \red{a} = { \frac{10}{10} }}}}$

${ \dashrightarrow{ \bf{ \red{a} = 1 \: m/s² }}}$

Hence acceleration of car is 1 m/s²