Question

A car is travelling on a path Badhe tables show the velocity of a car on each path at
different intervals of time.​

Answer 1

Answer:

Acceleration = change in velocity ÷ time taken for it

Acceleration for A to B= (20-0)÷10

4m/sec square

Acceleration From B to C= (30-20)÷5

2m/ sec square

Acceleration From C to D= (25-30)÷5

-1 m/sec square

Answer 2

Explanation:

$\sf{\underline{\large{For\: A \:to \:B :}}}$

$\sf{Given}\begin{cases}\sf{u=0 m/s}\\ \sf{v=20 m/s}\\ \sf{t = 10 s}\end{cases}$

Therefore,

$\sf{a = \frac{v-u}{t}}$

$\sf{\implies{a = \frac{20-0}{10}}}$

$\sf{\implies{a = \frac{20}{10}}}$

$\sf{\implies{\boxed{\sf{a =2 m/s^{2}}}}}$

$\sf{\underline{\large{Similarly, \:for \:B \:to \:C :}}}$

$\sf{Given}\begin{cases}\sf{u=20m/s}\\ \sf{v=30 m/s}\\ \sf{t = 5s}\end{cases}$

Therefore,

$\sf{a = \frac{v-u}{t}}$

$\sf{\implies{a = \frac{30-20}{5}}}$

$\sf{\implies{a = \frac{10}{5}}}$

$\sf{\implies{\boxed{\sf{a =2 m/s^{2}}}}}$

You can do so for C to D...

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