A car is travelling on a straight level road with the speed 54km/h it is followed by another car b which is moving with speed of 72km/h when the distance between them is5km,the driver of car b accelerat es his car at the rate of40km/h^2after what distance and time will car b Just catch up car a
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For B to catch A both will have to reach the same point in same time.
Let that distance be x . B will have to cover x+2kmin the same time.
For B equation will be
x=60km/hr×t
t=
60
x
hr
For A equation will be
x+2=70km/hr×
60
x
hr+
2
1
×−20km/hr
2
×(
60
x
)
2
x
2
−60x+720=0
The solution for the above equation using the quadratic formula will be
x=30(1±
2
)km
As we have to find the shortest distance, that distance will be
x=30(1−
2
)km
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