Question

A car is travelling with a speed of 36 km/h. The driver applied the brakes and retards

the car uniformly. The car is stopped in 5 sec. Find (i) The acceleration of car and (ii)

Distance before it stops after applying breaks?

Answer 1

u=36km/hr
v=0
t=5sec
a=v-u/t
a=-36/5
a=-7.2m/s²


part 2
2as=v²-u²
2a*-7.2=--1296
s=90m/s²

Answer 2

Answer:

Explanation:

v=u+at

v=0

u=36km/hr=10m/s

0= 10+5a

a=-2m/s^2

S=ut+1/2at^2

=50-25

S=25m