Question

A car is travelling with a speed of 36 km/hr. The driver applied the brakes and retards the car uniformly . The car is stopped in 5 sec. Find (1) the acceleration of car and (2) distance before it stops after appling brakes ?

Answer 1

Explanation:

u=36*5/18

=10m/s

V=0

T=5sec

V=u+at

0=10+5a

-10=5a

A=-10/5

A=5 m/s^2

V^2 =u^2 +2as

0=100+2*5*s

100+10s

S=100/10

S=10m

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