A car leaves Agra at 11 a.m. traveling at 50 km/h. How fast would a second car be travelled if it leaves Agra an hour later and overtakes the first car at 5 p.m. on the same day ?
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Answers
Answered by
29
11 a.m. to 5p.m. distance = 50 × 6
= 300 km
after one hour second car leaves at speed of
= 300/5
= 60km/hr
= 300 km
after one hour second car leaves at speed of
= 300/5
= 60km/hr
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Answered by
24
hey mate here's your answer......
we know that
distance = speed × time.
then distance travelled between 11am to 5 pm by 1st car = 50×6
= 300 km
so.... distance travelled by 2nd car is also equal for overtaking .....
and Time is 6-1 = 5
hence. speed = distance/time
= 300/ 5
= 60 km/hr
so the speed at which 2nd car is 60 km/hr
HOPE THIS HELPS YOU ☺☺
we know that
distance = speed × time.
then distance travelled between 11am to 5 pm by 1st car = 50×6
= 300 km
so.... distance travelled by 2nd car is also equal for overtaking .....
and Time is 6-1 = 5
hence. speed = distance/time
= 300/ 5
= 60 km/hr
so the speed at which 2nd car is 60 km/hr
HOPE THIS HELPS YOU ☺☺
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