a car mass 500 kg is.moving with a speed of 72 km/hr and brakes are aplied and car cokes to rest in 10 sec find the retardation and magnitude of force need to stop the car
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retardation
u=72*5/18=20m/s
v=0
t=10
a=v-u /t =0-20/10= -10m/s^2
force
m*a=500*-10=-5000
u=72*5/18=20m/s
v=0
t=10
a=v-u /t =0-20/10= -10m/s^2
force
m*a=500*-10=-5000
Answered by
0
Hi !
Initial velocity = u = 72 km/hr = 20 m/s
Final velocity = v = 0
Time = t = 10 sec
Acceleration [ retardation ] = a
a = v-u /t
= 0-20 /10
= -10m/s²
===========================================
mass = m = 500 kg
a = -10 m/s²
Force = ma
= 500 × -10
= -5000 N
Initial velocity = u = 72 km/hr = 20 m/s
Final velocity = v = 0
Time = t = 10 sec
Acceleration [ retardation ] = a
a = v-u /t
= 0-20 /10
= -10m/s²
===========================================
mass = m = 500 kg
a = -10 m/s²
Force = ma
= 500 × -10
= -5000 N
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