Question

A car moves 300 m towards north then 400 m towards west and finally 1200 m north. what is displacement of the car from initial position

Answer 1

∆f N
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∆ ∆i



let ∆i be initial position and ∆f be final position, then
let ∆ be the right ANGLE of triangle ∆.∆i.∆f
(displacement)^2 = (sum of north travelling)^2 +(sum of West traveling)^2

(displacement)^2 = 1500^2 + 400^2 = 2250000 + 160000 = 2410000
displacement = 100√241 m