A car moves at speed of 40 km/
Hr it is stopped by applying breaks which produces a uniform acceleration of -0.6m / s2. How much distance will the vehicle move before coming to stop
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Explanation:
The car is moving at a speed of 40 kmph .
Converting this in metres per second, it's 40 × 5/18
= 25 m/s.
It is stopped by applying breaks which produces an uniform acceleration of -0.6 m/s² .
Applying the third equation of motion
v² - u² = 2ax
Where x is the the distance the vehicle will move before stopping
v is 0( as it stops)
0 - 625 = 2×-0.6 x
1.2x = 625
x = 520 m approximately
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