A car moves in a straight line such that for a short time its velocity is defined by v=(3t2+2t)ft/s, where t is in seconds. determine its position and acceleration when t=3s, when t=0, s=0.
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Position is obtained by integrating velocity (v) with time (t).
Thus, position (S) = ∫ v dt = ∫ 3t² + 2t = t³ + t² + c
At t = 3 s, S = (3)³ + (3)² = 36 ft
Acceleration is obtained by taking derivative of velocity (v) with respect to time (t).
Thus, a = dv/dt = 6t + 2
At t = 3 s, a =20 ft/s²
Thus, position (S) = ∫ v dt = ∫ 3t² + 2t = t³ + t² + c
At t = 3 s, S = (3)³ + (3)² = 36 ft
Acceleration is obtained by taking derivative of velocity (v) with respect to time (t).
Thus, a = dv/dt = 6t + 2
At t = 3 s, a =20 ft/s²
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Answer:36m
Explanation:
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