Question

A car moves on a high way, the path trace by the car is shown below
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(i) What is the shape of the curve CDE?
(a) Parabolic
(b) Circle
(c) Straight line
(d) Ellipse
(ii)
If the shape of the curve ABC is represented by x2 - 7x + 12 then its zeroes are
(a) 2,-3
(b) 3,4
(c)4,-5
(d) 3, -5
(iii)
The path trace by the car, whose zeroes are 2 and - 4 is
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Answer 1

Answer:

(I) circle (ii) 4*3 are right answer

Answer 2

The shape of the curve CDE is parabola (option (a) ) , shape of the curve ABC is represented by $x^{2} -7x+12$  then its zeroes are 3 and 4 (option (b) ) , the path trace by the car, whose zeroes are 2 and - 4 is $x^{2} -2x-8$.

Given : A car moves on a high way, the path trace by the car is shown in the figure.

To Find : i ) The shape of the curve CDE

             (a) Parabolic

             (b) Circle

             (c) Straight line

             (d) Ellipse

ii ) If the shape of the curve ABC is represented by $x^{2} -7x+12$  then its zeroes are

(a) 2,-3

(b) 3,4

(c)4,-5

(d) 3, -5

iii) The path trace by the car, whose zeroes are 2 and - 4

Solution : The shape of the curve CDE is parabola (option (a) ) , shape of the curve ABC is represented by $x^{2} -7x+12$  then its zeroes are 3 and 4 (option (b) ) , the path trace by the car, whose zeroes are 2 and - 4 is $x^{2} -2x-8$.

i ) It is clear from the figure that the shape of the curve CDE is a parabola so option a) is correct.

ii ) If the shape of the curve ABC is represented by $x^{2} -7x+12$  then its zeroes are

$x^{2} -7x+12$ = 0

$(x-4) (x-3)$ = 0

$(x-4) = 0$ and $(x-3) = 0$

x = 4 and x = 3

So roots of the curve ABC is represented by $x^{2} -7x+12$ are 4 and 3

So option b) is correct.

iii ) The path trace by the car, whose zeroes are 2 and - 4

If the zeros of the equation are 2 and -4 then the equation will be

(x-4)(x+2)

= $x^{2} -2x-8$

So the path trace by the car, whose zeroes are 2 and - 4 is $x^{2} -2x-8$.

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