A car moves through 20 km at a speed of 40 km/h, and next 20 km at a speed of 60 km/h. Calculate its average speed.
Answers
Answered by
576
average speed of first
distance = 20 km
speed = 40 km/h
time taken = 20/40 = 1/2 hrs
2nd time average
distance = 20 km
speed = 60 km/h
time taken by the car is = 20/60 = 1/3 hrs
total time taken = t1+t2 = 1/2 +1/3 = 5/6 hrs
Average speed of the car is = (20+20)/(5/6)
= 48 km/h >===========================< ANSWER
distance = 20 km
speed = 40 km/h
time taken = 20/40 = 1/2 hrs
2nd time average
distance = 20 km
speed = 60 km/h
time taken by the car is = 20/60 = 1/3 hrs
total time taken = t1+t2 = 1/2 +1/3 = 5/6 hrs
Average speed of the car is = (20+20)/(5/6)
= 48 km/h >===========================< ANSWER
william:
we can use the formula of 2xy / x + y , where x = 40 & y = 60, therfore 2 * 40 * 60 / 40 + 60 = 48
Answered by
254
Distance = 20 km
Speed = 40 km/hr
Time, t1 = 20/40 = 1/2 hrs
Speed = 60 km/h
Time, t2 = 20/60 = 1/3 hrs
Total time = t1 + t2 = 1/2 + 1/3 = 5/6 hrs
Average speed = (20+20)/(5/6)
= 48 km/hr
Speed = 40 km/hr
Time, t1 = 20/40 = 1/2 hrs
Speed = 60 km/h
Time, t2 = 20/60 = 1/3 hrs
Total time = t1 + t2 = 1/2 + 1/3 = 5/6 hrs
Average speed = (20+20)/(5/6)
= 48 km/hr
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