Question

A car moves with a speed of 30km/h for 3 hours and then moves with a speed of 40km/h for 2 hours.what is the magnitude of the average velocity of the car?

Answer 1

Answer:

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Answer 2

The average velocity of the car is 34 km/h.

Given,

Speed of the car, V1=30 km/h

Time for which it runs at 30 km/h, t1=3 hours

Speed of the car, V2=40 km/h

Time for which it runs at 40 km/h, t2=2 hours.

To find,

the magnitude of the average velocity of the car.

Solution:

• Average velocity is equal to he ratio of the total displacement covered to the time taken to cover it.
• Average velocity is a vector quantity.

• Average velocity=Total displacement covered/Total time taken.

The distance, d1 that the car covers when it runs at 30 km/h for 3 hours,

$Speed=\frac{Distance}{Time} \\Distance=SpeedXTime\\Distance=30X3\\Distance=90 km.$

It covers 90 km while running at 30 km/h for 3 hours.

The distance, d2 that the car covers when it runs at 40 km/h for 2 hours,

$Speed=\frac{Distance}{Time} \\Distance=SpeedXTime\\Distance=40X2\\Distance=80 km.$

It covers 80 km while running at 40 km/h for 2 hours.

Let the average velocity of the car be V.

$V=\frac{(d1+d2)}{(t1+t2)} \\V=\frac{(90+80)}{(3+2)}\\V=\frac{170}{5} \\V=34 km/h.$

The car runs at an average velocity of 34 km/h.

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