Question

a car moves with a speed of 40km/h for 15 minutes and then with a speed of 60km/h for the next 15 minutes. The total distance covered by the car is
please friends help me to solve this question answer

Answer 1

simply use unitary method or applies the uniform motion equations

Answer 2

Given:

• The car moves with a speed of 40km/h for 15 minutes and then with a speed of 60km/h for the next 15 minutes.

To find:

• Net distance covered ?

Calculation:

The net distance covered will be equal to the product of speed and time taken by the car.

• Let the distance covered be d :

$\boxed{d = (v1 \times t1) + (v2 \times t2)}$

• Now, the units of speed and time has to be comparable .

• For example : 15 minutes = 15/60 = ¼ hours.

$\implies \: d = (40 \times \dfrac{1}{4} ) + (60 \times \dfrac{1}{4} )$

$\implies \: d = 10 + 15$

$\implies \: d = 25 \: km$

So, the net distance covered in this 30 minutes is 25 kilometers.