Question

A car moves with a speed of 60km/hr in east and with the same speed fir 30min in south. the displacement of car from initial position is

Answer 1

i guess this is ryt.

speed = 60km/hr

Time (t1)= 1hr , time(t2)=30min= 30/60= 1/2 hr

Distance travelled by a car in East direction(s1)= speed× t1 = 60× 1= 60km

Distance travelled by a car in south direction(s2)= speed× t1 = 60×1/2= 30 km

Displacement from intial position(s)= √(s1)²+(s²)²= √ (60)²+(30)²

= √3600+900

= √900(4+1)

= 30√5

Displacement= 30√5km

The displacement of car from initial position is 30√5km_