Question

a car moves with a velocity 10m/s towards east in 5s,its velocity changes to 10m/s towards north.then the change in velocity of car is

Answer 1

Answer:

2

$\ \sqrt[2]{2}$

Answer 2

Answer:

Change in velocity = 10j - 10î

Explanation:

Let us take the movement in the East direction as the positive x-axis movement and the movement in the North direction as the Movement in the positive y-axis.

Initially,

The velocity of the car = 10 m/s to East = 10î

The final velocity of the car = 10 m/s to North = 10j

So,

The change in velocity can be given by,

Final velocity - Initial Velocity = 10j - 10î

So,

Change in velocity = 10j - 10i

Magnitude of the change in the velocity can be given by,

$M=\sqrt{10^{2}+10^{2}}=\sqrt{200}\\M=10\sqrt{2}$

Therefore, the magnitude is 10√2 m/s.