Question

A car moves with speed 60 km/h for 1 hour in east direction and with same speed for 30 min in south direction . the displacement of car from initial position is

Answer 1

Given:
speed = 60km/hr
Time (t1)= 1hr , time(t2)=30min= 30/60= 1/2 hr

Distance travelled by a car in East direction(s1)= speed× t1 = 60× 1= 60km

Distance travelled by a car in south direction(s2)= speed× t1 = 60×1/2= 30 km

Displacement from intial position(s)= √(s1)²+(s²)²= √ (60)²+(30)²
= √3600+900
= √900(4+1)
= 30√5
Displacement= 30√5km
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The displacement of car from initial position is 30√5km
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Hope this will help you...

Answer 2

Answer:30√5km

speed = 60km/hr

Time (t1)= 1hr , time(t2)=30min= 30/60= 1/2 hr

Distance travelled by a car in East direction(s1)= speed× t1 = 60× 1= 60km

Distance travelled by a car in south direction(s2)= speed× t1 = 60×1/2= 30 km

Displacement from intial position(s)= √(s1)²+(s²)²= √ (60)²+(30)²

= √3600+900

= √900(4+1)

= 30√5

Displacement= 30√5km