Question

A car moves with velocity 10 m/s towards East in
5 s, its velocity changes to 10 m/s towards North
Then the change in velocity of car is

Answer 1

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Answer 2

Answer:

$\sqrt{200}\ m/s$

Explanation:

Let's consider that

V1 = 10 m/s towards north

V2 = 10 m/s towards east

Since, the angle between north and east is $90^o$ so angle between both velocity will also be $90^o$.

Since, the velocity is considered as vector quantity so we can't subtract both velocity directly.

We have to do vector sum for the subtraction of velocity. So, change in velocity will be $V=\sqrt{(V1)^{2}\ +\ (V2)^{2}+2.V1.V2.cos\theta }$

By, putting the value of V1, V2 and $\theta$ we will get

$V=\sqrt{(10)^{2}\ +\ (10)^{2}+2.10.10.cos90 }$

=> $V=\sqrt{200}$ m/s

So, the change in velocity will be $\sqrt{200}$ m/s.