Question

a car moving alone a straight highway WITH speed of 35M/s is brought to stop within a distance of 200M.how long does it take for the car to stop.

Answer 1

Answer:

~11.43 seconds

Explanation:

Let the time taken to stop the car be "t"

Acceleration of car = Change in velocity / Time

= (0 m/s - 35 m/s) / t

= -35/t

From equation of motion

S = ut + 0.5at²

200 = 35t + (0.5 × -35/t × t²)

200 = 35t - 17.5t

200 = 17.5t

t = 200/17.5 s

t ≈ 11.43 s