Question

a car moving along a straight highway with speed of 126 km/h is brought to a stop with in a distance of 200m what is the retardation of the car and how long does it take for the car to stop?​

Answer 1

Answer:

u=126 km/h=126×

18

5

m/s=35m/s

v=0

s=200m

Newton's Equation of motion

v

2

−u

2

=2as

0

2

−35

2

=2a(200)

a=−3.0625m/s

2

Also

v=u+at

0=35−3.06t

t=11.4s