A car moving along a straight road with a speed of 144 kilometre per hour is brought to a stop within a distance of 200 m how long does it take for the car to stop?
Answers
Given :
Speed of the car = 144 km/hr = 40m/s
Distance travelled to stop the car = 200m
To Find :
Time taken dor the car to stop
Solution :
- From equations of motion v² - u² = 2as
- By substituing the values in above equation
v² - u² = 2as
0 - 40² = 2×a×200
400a = -1600
a = -4 m/s²
- we also know ,v = u+at
0 = 40 + (-4)t
4t = 40
t = 10sec
The time taken by the car to stop is 10 sec
Answer:-
The car takes 10 seconds to stop.
Given:-
- Initial velocity (u) = 144 km/h
- Distance (s) = 200 m
To find:-
- Time taken to stop (t) = ?
Solution:-
Here, as the car will stop so it's final velocity (v) = 0
And,initial velocity = 144 km/h
★ Changing velocity into m/s
→ u = (144 × 1000)/(60 × 60)
→ u = 144000/3600
→ u = 40 m/s
First we have to find acceleration so we will use this formula:-
☛ v² = u² + 2as
→ 0² = (40)² + 2a × 200
→ 0 = 1600 + 400a
→ 400a = -1600
→ a = -1600/400
→ a = -4 m/s²
Now we will find out time, so we will use this formula:-
☛ v = u + at
→ 0 = 40 + (-4)t
→ 0 = 40 - 4t
→ 4t = 40
→ t = 40/4
→ t = 10 s
Therefore,