A car moving along in a straight highway from point p to point q to point r to point s, then back to point q and finally to point r as shown in the figure.
1) find the distance travelled by the car.
2) Find the displacement of the car.
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(a) As the car goes from O to P:
Since the car moves in a straight line, the distance will be equal to the displacement.
Total distance = Total displacement=360
The time taken by the car is=18 sec
Average speed of car is given by:
vavg=Total time takenTotal distance
=18360=20 m/s
Average velocity of the car is given by:
=Total time takenTotal displacement
=18360=20 m/s
(b)As the car goes from O to P and then back to O:
Total distance covered by car =360+(360−240)=360+120=480 m
The total displacement of car =240 m
Total time taken =18+6=24 sec
Average speed
=24480=20 m/s
Average velocity
=24240=10 m/s
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