Question

In triangle ABC, if A+B+C = pie, then the value of cos(a+b/2) is​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

A+B+C = 22/7

a+b = 22/7-C

Multiple by ( cos ) both side we have.

cos (a+b) = cos (22/7-c)

Divided by 2 both side

$\cos( \frac{a + b}{2} ) = \cos( \frac{22}{7 \times 2} - c)$

$\cos( \frac{a + b}{2} ) = \cos( \frac{11}{7} - c)$