Question

A car moving at 160km/hr when passes the mark A, driver applies brake and reduces its speed uniformly to 40km/hr at mark C. The marks are spaced at equal distances along the road. At which part of the track the car has instantaneous speed of 100km/hr. Neglect the size of car

Answer 1

The car has instantaneous speed of 100 km/hr between mark-B and mark-C.

Explanation:

From A to C : (40)^2−(160)^2 = 2a(AC)

From A to D : (100)^2−(160)^2 = 2a(AD)

Here D is the point where speed is 100 km/h.

From above AD = 13 / 20 (AC) and AB = AC / 2

We see that AD gt AB.

Thus the car has instantaneous speed of 100 km/hr between mark-B and mark-C.

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A car moving with speed of 50 km/hr,can be stopped by brakes after at least 6 m. if the same car is moving at a speed of 100 km/hr,the minimum stopping distance is ?

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