Question

A car moving at 30 m/s slows uniformly to a speed of 10 m/s in a time of 5 s. Determine
(a) The acceleration of the car.
(b) The distance it moves in the third second.

Answer 1

Answer:

u=30m/s

v=10 m/s

t=5 sec.

Acceleration =v-u/T

= 10-30/5= -30/5 = -6 m/s^2

Now t=3 sec

s=ut+1/2×(-a)×t^2

= 30t - 3/2 × t^2

= 30×3-3/2×3^2

s=63 m

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Answer 2

Answer:

$\bold{\red{(a) \:a = \frac{v - u}{t} }}$

$a = \frac{10 - 30}{5}$

$a = \frac{ - 20}{5}$

$a = - 4 \: m/{s}^{2}$

$\bold{\purple{(b)\: s = u + \frac{a}{2} (2n - 1)}}$

$s = 30 +( \frac{ - 4}{2} )(2 \times 3 - 1)$

$s = 30 + ( - 2)(5)$

$s = 30 - 10$

$s = 20 \: m$